Integrand size = 24, antiderivative size = 109 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=-\frac {8 i (a+i a \tan (c+d x))^7}{7 a^4 d}+\frac {3 i (a+i a \tan (c+d x))^8}{2 a^5 d}-\frac {2 i (a+i a \tan (c+d x))^9}{3 a^6 d}+\frac {i (a+i a \tan (c+d x))^{10}}{10 a^7 d} \]
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Time = 0.09 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {3568, 45} \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=\frac {i (a+i a \tan (c+d x))^{10}}{10 a^7 d}-\frac {2 i (a+i a \tan (c+d x))^9}{3 a^6 d}+\frac {3 i (a+i a \tan (c+d x))^8}{2 a^5 d}-\frac {8 i (a+i a \tan (c+d x))^7}{7 a^4 d} \]
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Rule 45
Rule 3568
Rubi steps \begin{align*} \text {integral}& = -\frac {i \text {Subst}\left (\int (a-x)^3 (a+x)^6 \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {i \text {Subst}\left (\int \left (8 a^3 (a+x)^6-12 a^2 (a+x)^7+6 a (a+x)^8-(a+x)^9\right ) \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {8 i (a+i a \tan (c+d x))^7}{7 a^4 d}+\frac {3 i (a+i a \tan (c+d x))^8}{2 a^5 d}-\frac {2 i (a+i a \tan (c+d x))^9}{3 a^6 d}+\frac {i (a+i a \tan (c+d x))^{10}}{10 a^7 d} \\ \end{align*}
Time = 0.64 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.72 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=-\frac {a^3 \sec ^9(c+d x) (\cos (7 (c+d x))+i \sin (7 (c+d x))) (-66 i+242 i \cos (2 (c+d x))+119 \sec (c+d x) \sin (3 (c+d x))+35 \tan (c+d x))}{840 d} \]
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Time = 182.42 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.83
method | result | size |
risch | \(\frac {128 i a^{3} \left (210 \,{\mathrm e}^{12 i \left (d x +c \right )}+252 \,{\mathrm e}^{10 i \left (d x +c \right )}+210 \,{\mathrm e}^{8 i \left (d x +c \right )}+120 \,{\mathrm e}^{6 i \left (d x +c \right )}+45 \,{\mathrm e}^{4 i \left (d x +c \right )}+10 \,{\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{105 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{10}}\) | \(91\) |
derivativedivides | \(\frac {-i a^{3} \left (\frac {\sin ^{4}\left (d x +c \right )}{10 \cos \left (d x +c \right )^{10}}+\frac {3 \left (\sin ^{4}\left (d x +c \right )\right )}{40 \cos \left (d x +c \right )^{8}}+\frac {\sin ^{4}\left (d x +c \right )}{20 \cos \left (d x +c \right )^{6}}+\frac {\sin ^{4}\left (d x +c \right )}{40 \cos \left (d x +c \right )^{4}}\right )-3 a^{3} \left (\frac {\sin ^{3}\left (d x +c \right )}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \left (\sin ^{3}\left (d x +c \right )\right )}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \left (\sin ^{3}\left (d x +c \right )\right )}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \left (\sin ^{3}\left (d x +c \right )\right )}{315 \cos \left (d x +c \right )^{3}}\right )+\frac {3 i a^{3}}{8 \cos \left (d x +c \right )^{8}}-a^{3} \left (-\frac {16}{35}-\frac {\left (\sec ^{6}\left (d x +c \right )\right )}{7}-\frac {6 \left (\sec ^{4}\left (d x +c \right )\right )}{35}-\frac {8 \left (\sec ^{2}\left (d x +c \right )\right )}{35}\right ) \tan \left (d x +c \right )}{d}\) | \(220\) |
default | \(\frac {-i a^{3} \left (\frac {\sin ^{4}\left (d x +c \right )}{10 \cos \left (d x +c \right )^{10}}+\frac {3 \left (\sin ^{4}\left (d x +c \right )\right )}{40 \cos \left (d x +c \right )^{8}}+\frac {\sin ^{4}\left (d x +c \right )}{20 \cos \left (d x +c \right )^{6}}+\frac {\sin ^{4}\left (d x +c \right )}{40 \cos \left (d x +c \right )^{4}}\right )-3 a^{3} \left (\frac {\sin ^{3}\left (d x +c \right )}{9 \cos \left (d x +c \right )^{9}}+\frac {2 \left (\sin ^{3}\left (d x +c \right )\right )}{21 \cos \left (d x +c \right )^{7}}+\frac {8 \left (\sin ^{3}\left (d x +c \right )\right )}{105 \cos \left (d x +c \right )^{5}}+\frac {16 \left (\sin ^{3}\left (d x +c \right )\right )}{315 \cos \left (d x +c \right )^{3}}\right )+\frac {3 i a^{3}}{8 \cos \left (d x +c \right )^{8}}-a^{3} \left (-\frac {16}{35}-\frac {\left (\sec ^{6}\left (d x +c \right )\right )}{7}-\frac {6 \left (\sec ^{4}\left (d x +c \right )\right )}{35}-\frac {8 \left (\sec ^{2}\left (d x +c \right )\right )}{35}\right ) \tan \left (d x +c \right )}{d}\) | \(220\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 215 vs. \(2 (85) = 170\).
Time = 0.23 (sec) , antiderivative size = 215, normalized size of antiderivative = 1.97 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=-\frac {128 \, {\left (-210 i \, a^{3} e^{\left (12 i \, d x + 12 i \, c\right )} - 252 i \, a^{3} e^{\left (10 i \, d x + 10 i \, c\right )} - 210 i \, a^{3} e^{\left (8 i \, d x + 8 i \, c\right )} - 120 i \, a^{3} e^{\left (6 i \, d x + 6 i \, c\right )} - 45 i \, a^{3} e^{\left (4 i \, d x + 4 i \, c\right )} - 10 i \, a^{3} e^{\left (2 i \, d x + 2 i \, c\right )} - i \, a^{3}\right )}}{105 \, {\left (d e^{\left (20 i \, d x + 20 i \, c\right )} + 10 \, d e^{\left (18 i \, d x + 18 i \, c\right )} + 45 \, d e^{\left (16 i \, d x + 16 i \, c\right )} + 120 \, d e^{\left (14 i \, d x + 14 i \, c\right )} + 210 \, d e^{\left (12 i \, d x + 12 i \, c\right )} + 252 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 210 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 120 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 45 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 10 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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\[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=- i a^{3} \left (\int i \sec ^{8}{\left (c + d x \right )}\, dx + \int \left (- 3 \tan {\left (c + d x \right )} \sec ^{8}{\left (c + d x \right )}\right )\, dx + \int \tan ^{3}{\left (c + d x \right )} \sec ^{8}{\left (c + d x \right )}\, dx + \int \left (- 3 i \tan ^{2}{\left (c + d x \right )} \sec ^{8}{\left (c + d x \right )}\right )\, dx\right ) \]
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Time = 0.48 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.99 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=-\frac {21 i \, a^{3} \tan \left (d x + c\right )^{10} + 70 \, a^{3} \tan \left (d x + c\right )^{9} + 240 \, a^{3} \tan \left (d x + c\right )^{7} - 210 i \, a^{3} \tan \left (d x + c\right )^{6} + 252 \, a^{3} \tan \left (d x + c\right )^{5} - 420 i \, a^{3} \tan \left (d x + c\right )^{4} - 315 i \, a^{3} \tan \left (d x + c\right )^{2} - 210 \, a^{3} \tan \left (d x + c\right )}{210 \, d} \]
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Time = 0.60 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.99 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=-\frac {21 i \, a^{3} \tan \left (d x + c\right )^{10} + 70 \, a^{3} \tan \left (d x + c\right )^{9} + 240 \, a^{3} \tan \left (d x + c\right )^{7} - 210 i \, a^{3} \tan \left (d x + c\right )^{6} + 252 \, a^{3} \tan \left (d x + c\right )^{5} - 420 i \, a^{3} \tan \left (d x + c\right )^{4} - 315 i \, a^{3} \tan \left (d x + c\right )^{2} - 210 \, a^{3} \tan \left (d x + c\right )}{210 \, d} \]
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Time = 3.80 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.39 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^3 \, dx=-\frac {a^3\,\sin \left (c+d\,x\right )\,\left (-210\,{\cos \left (c+d\,x\right )}^9-{\cos \left (c+d\,x\right )}^8\,\sin \left (c+d\,x\right )\,315{}\mathrm {i}-{\cos \left (c+d\,x\right )}^6\,{\sin \left (c+d\,x\right )}^3\,420{}\mathrm {i}+252\,{\cos \left (c+d\,x\right )}^5\,{\sin \left (c+d\,x\right )}^4-{\cos \left (c+d\,x\right )}^4\,{\sin \left (c+d\,x\right )}^5\,210{}\mathrm {i}+240\,{\cos \left (c+d\,x\right )}^3\,{\sin \left (c+d\,x\right )}^6+70\,\cos \left (c+d\,x\right )\,{\sin \left (c+d\,x\right )}^8+{\sin \left (c+d\,x\right )}^9\,21{}\mathrm {i}\right )}{210\,d\,{\cos \left (c+d\,x\right )}^{10}} \]
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